How many grams of cesium chloride (CsCl) will be needed to make 750. mL of a 0.100 M CsCl aqueous solution? The formula mass of CsCl is 168.36 g/mol
mols needed = M x L = ?
Then grams = mols x molar mass = ?
To find the number of grams of CsCl needed, we can use the formula:
grams = moles × molar mass
First, let's calculate the number of moles of CsCl needed in the solution.
moles = volume × concentration
The volume of the solution is given as 750 mL, but we need it in liters for the calculation. Since 1 liter is equal to 1000 mL:
volume = 750 mL ÷ 1000 = 0.75 L
The concentration of the solution is given as 0.100 M, where M represents moles per liter. Therefore, the concentration is already in moles per liter.
moles = 0.75 L × 0.100 mol/L = 0.075 mol
Now, we can find the number of grams of CsCl needed by multiplying the moles by the molar mass of CsCl.
grams = 0.075 mol × 168.36 g/mol = 12.627 g
So, approximately 12.627 grams of cesium chloride (CsCl) will be needed to make 750 mL of a 0.100 M CsCl aqueous solution.