a motor car accelerates for 10seconds to attain a velocity of 20m/s2 . it continues with uniform velocity for a further 20seconds and then decelerates so that it steps in 20seconds. calculate the acceleration and deceleration?
acceleration = 20m/s รท 10s = 2 m/s^2
deceleration takes twice as long, so it is half as much.
A motor car accelerate for 10 sec to attain a velocity of 20 MLS, it continues with uniform that it stops further 20 sec calculate 1acceleratio 2deceleration 3distance travel
A Car Starting From Rest Is Acceleratted Uniformly To A Velocity Of 100.8K/L covert this to meter persecond.
What of the last questions answer
Show the workings steps by step
Acceleration:
a=change in velocity(v)/time(t)
Acceleration 20m/s deceleration 30seconds
Pls show the workings step by step so we can understand well
a motor car accelerate for 10sec attain a velocity of 20m/s. it continues with uniform velocity fir a further 20sec then decelerate so that if stops in the second calculate the acceleration
A motor car accelerates for 10sec to attain a
velocity of 20m/s. it continues with uniform
velocity for a further 20sec and then decelerates
so that it stops in 20sec. calculate
I) acceleration
ii) deceleration
iii) the distance traveled?