If 0.5 moles of bacl2 is mixed with 0.2 moles na3po4 then maximum no.of moles of nacl formed is?
the sodium is the limiting reactant
.6 moles
To determine the maximum number of moles of NaCl formed when 0.5 moles of BaCl2 and 0.2 moles of Na3PO4 are mixed, we need to find the limiting reagent. The limiting reagent is the reactant that will be completely consumed and determines the maximum amount of product that can be formed.
First, we should write the balanced chemical equation for the reaction between BaCl2 and Na3PO4:
3BaCl2 + 2Na3PO4 → Ba3(PO4)2 + 6NaCl
From the balanced equation, we can see that the stoichiometric ratio between BaCl2 and NaCl is 3:6 or 1:2. This means that for every 3 moles of BaCl2, we can obtain 6 moles of NaCl.
Now let's determine the moles of NaCl that can be formed:
- For BaCl2: we have 0.5 moles, and the stoichiometric ratio is 1:2. Therefore, we can form 0.5 x 2 = 1 mole of NaCl.
- For Na3PO4: we have 0.2 moles, and the stoichiometric ratio is 2:6. Therefore, we can form 0.2 x (6/2) = 0.6 moles of NaCl.
Since the formation of NaCl is limited by the reactant that produces fewer moles, the maximum number of moles of NaCl that can be formed is 0.6 moles.
Therefore, the maximum number of moles of NaCl formed is 0.6 moles.