a plane flies northwards for 430km.if the plane flies eastward for 380km.how far is it from its starting point(ignore its height above the ground)
John Lee is wrong.
184,900 + 114,400 = x^2
329,300 = x^2
573.8 = x
430^2 + 380^2 = x^2
Square root everything:
430+380=x
810=x
Ms.Sue there is a little error in your calculations.
Square everything on left hand side :
430^2 + 380^2 = x^2
= 184,900 + 144,400 = x^2
Add up left hand side
= 329,300 = x^2
Square both side
573.8 = x
x = 574km
To find the distance from the starting point, we can use the Pythagorean theorem, which states that in a right triangle, the square of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides.
In this case, the northward distance of 430 km and the eastward distance of 380 km form the two perpendicular sides of our right triangle. Let's denote the northward distance as 'a' and the eastward distance as 'b.' The distance from the starting point (the hypotenuse) can be represented as 'c'.
Using the Pythagorean theorem, we can write the equation:
a² + b² = c²
Substituting the given values:
430² + 380² = c²
Simplifying:
184,900 + 144,400 = c²
329,300 = c²
To calculate the value of 'c', we can take the square root of both sides:
√329,300 = √(c²)
c ≈ √329,300
Therefore, the distance from the starting point (ignoring the plane's height above the ground) is approximately equal to the square root of 329,300 km.