Arrangethe increasing of bp for given molecule and given reason h2o, h2s, h2se. H2te
To arrange the given molecules (H2O, H2S, H2Se, and H2Te) in increasing order of boiling point, we need to consider their molecular structure, molecular weight, and intermolecular forces.
1. H2S (Hydrogen sulfide): It is a nonpolar molecule with a bent shape (V-shaped geometry) due to the lone pair on the sulfur atom. It has a lower molecular weight compared to the others. H2S exhibits dipole-dipole interactions and London dispersion forces. The boiling point of H2S is relatively low due to weaker intermolecular forces.
2. H2Se (Hydrogen selenide): It is also a nonpolar molecule with a bent shape. Like H2S, H2Se has dipole-dipole interactions and London dispersion forces. However, the boiling point of H2Se is higher than that of H2S because selenium is a heavier atom, and heavier atoms experience stronger London dispersion forces.
3. H2O (Water): Water is a polar molecule with a bent shape due to the lone pairs on the oxygen atom. It has stronger dipole-dipole interactions and hydrogen bonding, in addition to London dispersion forces. The boiling point of water is higher than that of H2Se and H2S due to the presence of hydrogen bonding, which is a stronger intermolecular force than dipole-dipole interactions and London dispersion forces.
4. H2Te (Hydrogen telluride): H2Te is a polar molecule with a bent shape, similar to H2S and H2Se. It has dipole-dipole interactions and stronger London dispersion forces due to the heavier tellurium atom. However, its boiling point is significantly higher than the others because tellurium is a much heavier atom, resulting in stronger London dispersion forces.
Arranging the molecules in increasing order of boiling point:
H2S < H2Se < H2O < H2Te
So, the increasing order of boiling point for the given molecules is H2S, H2Se, H2O, and H2Te.