A boy walks 25.0 m to the north and then turns around and walks 11.0 m south. Boys! What is the 1) distance he has traveled and, 2) the magnitude of his displacement.

A.4.0 m, 36.0 m

B.36.0 m, 14.0 m

C.36.0 m, 36.0 m

D.14.0 m, 14.0 m

You should get a better First Name. A physics tutor might actually help you if you do.

A boy walks 25.0 m to the north and then turns around and walks 11.0 m south. Boys! What is the 1) distance he has traveled and, 2) the magnitude of his displacement.

A.4.0 m, 36.0 m

B.36.0 m, 14.0 m

C.36.0 m, 36.0 m

D.14.0 m, 14.0 m

To answer this question, we need to understand the concepts of distance and displacement. Distance is the total length of the path traveled, while displacement is the straight-line distance between the initial and final positions.

First, let's calculate the distance traveled by the boy. He walks 25.0 m to the north and then turns around and walks 11.0 m south. To find the total distance, we add the two distances together:

Distance = 25.0 m + 11.0 m = 36.0 m

So, the boy has traveled a distance of 36.0 m.

Now, let's calculate the magnitude of his displacement. Displacement involves considering only the straight-line distance between the initial and final positions.

The boy walks 25.0 m to the north and then changes direction and walks 11.0 m south. This means he ends up 11.0 m below his starting position.

Displacement = 11.0 m (south)

Therefore, the magnitude of his displacement is 11.0 m.

So, the correct answer is option B. The boy has traveled a distance of 36.0 m and has a displacement of 11.0 m.