Naron is learning for pre-second semester examination. He divides 8 hours per day for learning science, mathematics and literature with the ratio of 2 : 3 : 1. Find the number of hours he studies each major.
2+3+1=6 therefore science=(2/6)*8=2.67 and math=(3/6)*8=4 hours
let the times for the 3 subjects be 2x, 3x and x hrs each
2x+3x+x = 8
6x=8
x = 4/3
science : 2(4/3) = 8/3 hrs or 2 hrs and 40 minutes
Math : 3(4/3) = 4 hours
Lit : 4/3 hrs or 1 hour and 20 minutes
check: 2:40 + 4:00 + 1:20 = 6:00
To solve this problem, we need to determine the number of hours Naron studies each major based on the given ratio of 2:3:1.
Step 1: Calculate the total ratio
The total ratio is found by adding up the individual ratios: 2 + 3 + 1 = 6.
Step 2: Calculate the number of hours per ratio unit
Divide the total number of hours Naron studies per day (8 hours) by the total ratio (6) to find the number of hours per ratio unit:
8 hours / 6 units = 1.33 hours per unit (approximately).
Step 3: Calculate the number of hours for each major
Multiply the number of hours per ratio unit by the corresponding ratio for each major:
Science: 2 units * 1.33 hours/unit = 2.67 hours (approximately)
Mathematics: 3 units * 1.33 hours/unit = 4 hours (approximately)
Literature: 1 unit * 1.33 hours/unit = 1.33 hours (approximately)
Therefore, Naron studies science for approximately 2.67 hours, mathematics for approximately 4 hours, and literature for approximately 1.33 hours.