Find the concentrations of all species in a 0.10mol/l solution of NaOH

(Na^+) = 0.10 M

(OH^-) = 0.10 M
(H^+) = Kw/(OH^-) = ?

To find the concentrations of all species in a solution of NaOH, we need to consider the dissociation of NaOH in water. NaOH dissociates into Na+ and OH- ions.

The balanced chemical equation for the dissociation of NaOH is:

NaOH(aq) -> Na+(aq) + OH-(aq)

Since NaOH is a strong electrolyte, it completely dissociates in water. This means that for every 1 mole of NaOH, we will have 1 mole of Na+ ions and 1 mole of OH- ions.

Given that the concentration of the NaOH solution is 0.10 mol/L, the concentration of Na+ ions and OH- ions will also be 0.10 mol/L.

Therefore, in a 0.10 mol/L solution of NaOH, the concentrations of all species are as follows:

- Na+: 0.10 mol/L
- OH-: 0.10 mol/L