Find the cost of 3 notebooks and 1 magazine in terms of y, if the cost of 1 notebook is 2y and that of 1 magazine is (y+3) ?
that would be
3(2y) + 1(y+3) = 6y+y+3 = 7y+3
This is how you solve the problem.
3n+1n=0
3(2y)+1(y+3)=0
6y+y+3=0
7y+3=0
7y+3-3=0-3
7y=-3
7y/7=-3/7
y=-3/7
To find the cost of 3 notebooks and 1 magazine in terms of y, we need to multiply the cost of each item by its quantity.
Given that the cost of 1 notebook is 2y and 1 magazine is (y+3), we can calculate the total cost as follows:
Cost of 3 notebooks = 3 * (2y) = 6y
Cost of 1 magazine = 1 * (y+3) = y+3
Therefore, the total cost of 3 notebooks and 1 magazine in terms of y is 6y + (y+3).