The sum of the measures of the angles of any triangle is 180 degrees. In triangle ABC, the

measure of angle A is 70° more than the measure of angle B. The measure of angle B is twice
the measure of angle C. Find the measure of each angle.

a-70=b

b=2c
a+b+c=180
b+70+2c+c=180
2c+70+3c=
5c=110
c=22 deg
b=44 deg
a=114 deg

To solve this problem, we can set up equations based on the given information.

Let's assign variables to represent the measures of angles B and C. We'll call angle B "x" and angle C "y".

Based on the information given, we can write the following equations:

1) The measure of angle A is 70° more than the measure of angle B:
A = B + 70°

2) The measure of angle B is twice the measure of angle C:
B = 2C

3) The sum of the measures of the angles of any triangle is 180 degrees:
A + B + C = 180°

Now we can substitute the second equation into the first equation to eliminate B:

A = 2C + 70°

Substituting the values of A and B into the third equation:

(2C + 70°) + (2C) + C = 180°

Simplifying the equation:

5C + 70° = 180°
5C = 110°
C = 22°

Now that we have the value of C, we can substitute it back into the second equation to find B:

B = 2C = 2 * 22° = 44°

Finally, we can substitute the values of B and C into the first equation to find A:

A = B + 70° = 44° + 70° = 114°

Therefore, the measure of angle A is 114°, the measure of angle B is 44°, and the measure of angle C is 22°.