Suppose that 12.41 mL of 0.169 M NaOH(aq) was required to titrate 0.1579 g of an unknown acid (HX). What is the molar mass of the acid?
Answer in units of g/mol.
both are monoprotic, so moles acid=molesbase
.1579/MolmassAcid=.01241*.169
solve for mole mass of acid