The pressure P of a gas varies inversely with its volume, V. Pressure is measured in units of Pa. Suppose that A particular amount of a gas is initially at a pressure of 104 Pa at a volume of 108 L. If the volume is expanded to 432 L , what will the new pressure be ?
so tis 26 Pa
yw :]
To find the new pressure, we can use the inverse variation formula:
P1 * V1 = P2 * V2
where P1 is the initial pressure, V1 is the initial volume, P2 is the new pressure, and V2 is the new volume.
Given:
P1 = 104 Pa
V1 = 108 L
V2 = 432 L
Substituting these values into the formula, we get:
104 * 108 = P2 * 432
Simplifying the equation:
11232 = 432P2
To find P2, we can divide both sides of the equation by 432:
11232 / 432 = P2
P2 ≈ 26 Pa
Therefore, the new pressure will be approximately 26 Pa when the volume is expanded to 432 L.
To determine the new pressure when the volume is expanded to 432 L, we can use the inverse variation formula:
P₁ * V₁ = P₂ * V₂
Where:
- P₁ is the initial pressure (104 Pa)
- V₁ is the initial volume (108 L)
- P₂ is the new pressure (to be determined)
- V₂ is the new volume (432 L)
Let's solve for P₂:
P₁ * V₁ = P₂ * V₂
Substituting the given values:
104 Pa * 108 L = P₂ * 432 L
Rearranging the equation and solving for P₂:
P₂ = (104 Pa * 108 L) / 432 L
P₂ = 26 Pa
Therefore, the new pressure when the volume is expanded to 432 L will be 26 Pa.
p = k/v
or
p v = k
so
P2 V2 = P1 V1
P2 = (V1/V2) P1
P2 = (108/432)(104)