To get to school, you need to walk 9 blocks south and then 12 blocks east. What's the diagonal distance from the start.
Ah -- good old Pythagoras!
a^2 + b^2 = c^2
9^2 + 12^2 = c^2
81 + 144 = c^2
225 = c^2
15 = c
15 blocks
To find the diagonal distance, we can use the Pythagorean theorem. The theorem states that in a right triangle, the square of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides.
In this case, the lengths of the two sides are the 9 blocks south and 12 blocks east. Let's call the diagonal distance "D".
Using the Pythagorean theorem:
D^2 = (9^2) + (12^2)
D^2 = 81 + 144
D^2 = 225
To find D, we take the square root of both sides:
D = √225
D = 15
Therefore, the diagonal distance from the start to school is 15 blocks.
To find the diagonal distance from the start to school, we can use the Pythagorean theorem. The Pythagorean theorem states that in a right-angled triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the lengths of the other two sides.
In this case, the distance walked south and the distance walked east form the two legs of the right-angled triangle. The diagonal distance from the start to school is the hypotenuse of this triangle.
To calculate the diagonal distance, we can use the formula:
diagonal distance = √(south distance^2 + east distance^2)
In this case, the south distance is 9 blocks and the east distance is 12 blocks. Plugging these values into the formula, we get:
diagonal distance = √(9^2 + 12^2)
diagonal distance = √(81 + 144)
diagonal distance = √225
diagonal distance = 15
Therefore, the diagonal distance from the start to school is 15 blocks.