"Solve each equation. Round your answers to the nearest ten-thousandth." (These are my directions)

Here is the equation: 3^n + 9 = 69

How do I solve this getting the answer asked for?

solve each equation?

hmmm-well Suggested solution
log3^n+log9=log69
log3^n=log69-log9
n=(log69-log9)/log3
find n then round up

You cannot take log of individual terms, you have to take log of both sides.

i.e. log (3^n + 9) = 69

but , why not just do this:
3^n = 60
now log both sides, and use log rules:
n log3 = log60
n = log60/log2 = appr 3.727

check:
3^3.727 + 9 = 69.01100 , close enough to 69

if you meant:
3^(n+9) = 69
(n+9)log3 = log 69
n+9 = log 69/log3
n = log69/log3 - 9

To solve the equation 3^n + 9 = 69 and round your answer to the nearest ten-thousandth, follow these steps:

1. Subtract 9 from both sides of the equation to isolate the exponential term: 3^n = 69 - 9 = 60.

2. Take the logarithm of both sides of the equation using the base 3: log(base 3)(3^n) = log(base 3)(60).

3. The logarithm of the base raised to an exponent is equal to the exponent, so the equation simplifies to: n = log(base 3)(60).

4. Use a calculator to evaluate the logarithm to get the value of n. Round the answer to the nearest ten-thousandth as specified in the directions.

For example, if the calculator gives you n = 3.7885318, rounding to the nearest ten-thousandth would give you n = 3.7885 as your final answer.