Six apples cost as much as four pears. Each pear costs $4 more than each Apple. What is the cost of one pear?
6A = 4P
A = 4/6P = 1/3P
P = A + 4
Substitute P/3 for A in the third equation and solve for P.
Or you could try it this way.
P-4 = A
6A = 4P
Substitute P-4 for A in the second equation and solve for P.
However, something seems askew here. Typos?
Each pear costs $4 more than each Apple ---
p = a + 4
Now , that's some expensive fruit !!
6a = 4p
6a = 4(a+4)
6a = 4a + 16
2a = 16
a = 8 , then p = 12
An apple costs $4 and a pear costs $12
WOW, but the answers check out for you info
To find the cost of one pear, we can start by assigning variables to the costs of apples and pears. Let's say the cost of one apple is 'A' and the cost of one pear is 'P'.
According to the given information, six apples cost as much as four pears, which can be expressed as:
6A = 4P
We are also told that each pear costs $4 more than each apple:
P = A + $4
Now we can solve these two equations to find the value of 'P'.
First, let's substitute the second equation into the first equation:
6A = 4(A + $4)
Next, distribute the 4 to each term inside the parentheses:
6A = 4A + $16
Combine like terms by subtracting 4A from both sides:
6A - 4A = $16
2A = $16
Next, divide both sides of the equation by 2 to solve for 'A':
A = $8
Now that we know the cost of one apple, let's substitute this value into the second equation to find the cost of one pear:
P = $8 + $4
P = $12
Therefore, the cost of one pear is $12.