A truck with a mass of 2.00x10^3 kg is coasting along a straight level road at 250.0 m/s. It comes to rest in 300.0m. How much work is done by friction in bring the truck to a stop?

vf^2=vi^2 + 2 a*d

solve for a. But a=frictionforce/mass
then solve for friction force.

To find the work done by friction in bringing the truck to a stop, we can use the work-energy principle. According to this principle, the work done on an object is equal to the change in its kinetic energy.

The formula for work is given by:

Work = Force × Distance × Cos(θ)

In this case, the force in question is the force of friction acting on the truck, and the distance is the distance over which the truck comes to a stop.

First, let's calculate the initial kinetic energy (K.E.) of the truck. The formula for kinetic energy is given by:

K.E. = (1/2) × Mass × Velocity^2

Substituting the given values:

K.E. = (1/2) × (2.00 × 10^3 kg) × (250.0 m/s)^2

Next, we need to find the final kinetic energy of the truck when it comes to a stop. Since the truck comes to rest, the final kinetic energy is 0.

Now, we can calculate the work done by friction:

Work = Final K.E. - Initial K.E.

Work = 0 - Initial K.E.

Remember, the work done by friction on the truck is equal to the work done against the truck's motion. Thus, the work done by friction is equal in magnitude but opposite in sign to the initial kinetic energy.

Substituting the values into the equation:

Work = -((1/2) × (2.00 × 10^3 kg) × (250.0 m/s)^2)

Calculating the value will give you the work done by friction in bringing the truck to a stop.