root(3,12m^2)
Trying to figure out how to rewrite as an expression with a fractional exponent.Thank you for your help
root(3,12m^2)
Not sure why you have two arguments to root. Do you mean cube root?
If so, then you just have 12^(1/3) m^(2/3)
Then nth-root is just the (1/n) power. Plug it in and then just use the normal exponent operations.
To rewrite the expression √(3,12m^2) with a fractional exponent, we first need to understand what the fractional exponent represents. In general, an exponent represents how many times a number should be multiplied by itself. A fractional exponent is a way to express a root.
In this case, the expression √(3,12m^2) represents the cube root of 12m^2. The cube root means finding a number that, when raised to the power of 3, gives us 12m^2.
To rewrite this with a fractional exponent, we can use the fact that n√x = x^(1/n). In other words, the nth root of x is equal to x raised to the power of 1/n.
Applying this to the expression, the cube root of 12m^2 can be rewritten as (12m^2)^(1/3).
Therefore, the expression √(3,12m^2) written as an expression with a fractional exponent is (12m^2)^(1/3).
I hope this explanation helps! Let me know if you have any further questions.