Three bottles of aqueous solutions are discovered in an abandoned lab. The solutions are green, yellow and purple. It is known that three complex ions of chromium (III) were commonly used in that lab: [Cr(H2O)6]3+, [Cr(NH3)6]3+, [Cr(H2O)4Cl2]+. What is the likely identity of each colored
solution?
would it depend on the ligand?, for [Cr(H2O)6]^3+, since h2o is weak it has a small delta value thus a high spin and Since its weak, on the color wheel it would be green? [Cr(Nh3)6]^3+, NH3 is strongest of all so its color is yellow, than last is green?
correction :
last is violet
i know answers now nevermind.
To determine the likely identity of each colored solution based on the three complex ions of chromium (III), we can analyze the color and the ligands present in each complex ion.
1. [Cr(H2O)6]3+: This complex ion consists of 6 water molecules as ligands. It is usually a pale green color. Therefore, it is likely that the green solution corresponds to [Cr(H2O)6]3+.
2. [Cr(NH3)6]3+: This complex ion consists of 6 ammonia molecules as ligands. It usually has a deep purple color. Therefore, the purple solution is likely to be [Cr(NH3)6]3+.
3. [Cr(H2O)4Cl2]+: This complex ion contains 4 water molecules and 2 chloride ions as ligands. It has a yellow color. Therefore, the yellow solution is likely to be [Cr(H2O)4Cl2]+.
In conclusion, the likely identity of each colored solution is as follows:
- Green solution: [Cr(H2O)6]3+
- Purple solution: [Cr(NH3)6]3+
- Yellow solution: [Cr(H2O)4Cl2]+.