concrete is to be mixed using cement and sand into the ratio 2:5. how much sand will be required to mix with 96 pounds of cement? use proportion to solve
2/5 = 96/s
Cross multiply and solve for s.
To find out how much sand is required to mix with 96 pounds of cement in a ratio of 2:5, we can set up a proportion using the given ratio.
The ratio of cement to sand is 2:5, which means for every 2 parts of cement, we need 5 parts of sand.
Let's assume "x" represents the amount of sand required.
The proportion can be set up as:
2/5 = 96/x
To solve this proportion, we can cross-multiply:
2x = 5 * 96
2x = 480
Next, divide both sides of the equation by 2 to isolate "x":
x = 480/2
x = 240
Therefore, 240 pounds of sand will be required to mix with 96 pounds of cement in a ratio of 2:5.