Acidic soil sample collected from HagreSelam location of southern Ethiopia was analysed in the laboratory had exchangeable Al content of 4.5 meq/100 gram of soils and its bulk density was found to be 1.25 g/cm3. Based on this information calculate the amount of lime required to be applied per hectare at 15 cm depth to neutralizer the acidity of this soils.

To calculate the amount of lime required to neutralize the acidity of the soil, we need to follow these steps:

Step 1: Calculate the lime requirement per hectare.

First, we need to convert the exchangeable aluminum (Al) content from meq/100g to cmol/kg, which is the unit commonly used for lime requirements.

1 meq/100g = 0.01 cmol/kg

Therefore, the exchangeable Al content in cmol/kg is:
4.5 meq/100g * 0.01 cmol/kg = 0.045 cmol/kg

Step 2: Convert the soil bulk density from g/cm3 to t/ha.

1 g/cm3 = 10 t/ha

Therefore, the soil bulk density in t/ha is:
1.25 g/cm3 * 10 t/ha = 12.5 t/ha

Step 3: Calculate the lime requirement based on the exchangeable Al content.

The general formula for calculating the liming requirement is:
Lime requirement (t/ha) = Exchangeable Al (cmol/kg) * Bulk density (t/ha)

Substituting the values we have:
Lime requirement = 0.045 cmol/kg * 12.5 t/ha

Lime requirement = 0.5625 t/ha

So, the lime requirement per hectare at a 15 cm depth to neutralize the acidity of this soil sample is 0.5625 tonnes.