How many grams of solute are required to make a 976 mL solution of sodium hydroxide with a concentration of 0.0783 M?
molarity=moles/volume
= gramssolute/molmass*volume
gramssolute=molarity*molmass*volume
= .0783*40*.976 grams
To determine the number of grams of solute required to make a 976 mL solution of sodium hydroxide with a concentration of 0.0783 M, you need to use the formula:
grams of solute = moles of solute × molar mass of solute
First, we need to calculate the moles of solute using the formula:
moles of solute = volume of solution (in L) × concentration of solution (in M)
The volume of solution is given in mL, so we need to convert it to liters by dividing by 1000:
volume of solution = 976 mL ÷ 1000 = 0.976 L
Now we can substitute the values into the formula:
moles of solute = 0.976 L × 0.0783 M = 0.076428 mol
Next, we need to determine the molar mass of sodium hydroxide (NaOH). The molar mass of an element or compound is calculated by adding up the atomic masses of its constituent elements.
The atomic masses are as follows:
- Na (Sodium) = 22.99 g/mol
- O (Oxygen) = 16.00 g/mol
- H (Hydrogen) = 1.01 g/mol
So, the molar mass of NaOH = (22.99 g/mol) + (16.00 g/mol) + (1.01 g/mol) = 40.00 g/mol
Finally, we can calculate the grams of solute:
grams of solute = 0.076428 mol × 40.00 g/mol = 3.057 g
Therefore, you would need 3.057 grams of sodium hydroxide to make a 976 mL solution with a concentration of 0.0783 M.