A 1370-kg car is skidding to a stop along a horizontal surface. The car decelerates from 27.6 m/s to a rest position in 3.15 seconds. What is the frictional force that the skidding car experiences?
average velocity=27.6/2 m/s
distance=avgvel*time figure that.
vf^2=vi^2+2ad
but a= frictionforce/mass
solve for frictional force.
To find the frictional force experienced by the skidding car, we can use Newton's second law of motion, which states that the force acting on an object is equal to its mass multiplied by its acceleration.
In this case, the car is decelerating, so its acceleration is negative. Let's denote the initial velocity of the car as v0, the final velocity as vf, the acceleration as a, and the mass of the car as m.
Given:
Initial velocity, v0 = 27.6 m/s
Final velocity, vf = 0 m/s (since the car comes to a rest)
Acceleration, a = ?
Mass, m = 1370 kg
We can use the formula:
vf = v0 + at
Rearranging the formula to solve for acceleration (a):
a = (vf - v0) / t
Substituting the given values:
a = (0 - 27.6) m/s / 3.15 s
Calculating the acceleration:
a = -8.762 m/s²
The negative sign indicates that the car is decelerating (slowing down).
Now, we can use Newton's second law to find the force:
F = ma
Substituting the values:
F = (1370 kg)(-8.762 m/s²)
Calculating the force:
F = -11,999 N
The frictional force experienced by the skidding car is approximately 11,999 Newtons directed opposite to the car's motion.