A tank was 1/5 full .When another 700 ml of water was poured into the tank , it became2/3 full .Find the capacity
Let c be the capacity of the tank
(1/5)x + 700 = (2/3)x
times 15, the LCD
3x + 10500 =10x
7x=10500
x = 1500
The tank holds 1500 ml or 1.5 L
Well, let's do some math and clown around with numbers!
If the tank was originally 1/5 full and then 700 ml of water was added, it became 2/3 full.
So, the difference between being 1/5 full and 2/3 full is 2/3 - 1/5.
Now, let's find the common denominator for these fractions. The least common multiple of 3 and 5 is 15.
So, 1/5 becomes 3/15 and 2/3 becomes 10/15.
The difference between these fractions is 10/15 - 3/15, which gives us 7/15.
Since we know that 700 ml is equivalent to 7/15 of the tank's capacity, we can set up a proportion.
7/15 = 700 ml/x, where x represents the capacity of the tank.
Multiplying both sides of the equation by x, we get 7x/15 = 700 ml.
To find the value of x, we can cross multiply.
7x = 700 ml * 15
7x = 10500 ml
Now, let's solve for x.
x = 10500 ml / 7
x = 1500 ml
So, the capacity of the tank is 1500 ml.
Now that the math is done, let's celebrate with a clown dance! 🎉🤡
Let's assume the capacity of the tank is represented by 'x' ml.
Given that the tank was initially 1/5 full, we can calculate the amount of water in the tank at that point:
Amount of water in the tank initially = (1/5) * x
When 700 ml of water was poured into the tank, it became 2/3 full. So, the amount of water in the tank after pouring the water can be calculated as follows:
Amount of water in the tank after pouring = (2/3) * x
According to the given information, the difference between the amount of water before and after pouring is 700 ml.
So, we can set up the equation as follows:
(2/3) * x - (1/5) * x = 700
To solve the equation, we can find a common denominator:
(10/15) * x - (3/15) * x = 700
Simplifying the equation gives:
(7/15) * x = 700
To isolate 'x', we can multiply both sides of the equation by 15/7:
x = (700 * 15) / 7
Simplifying the expression gives:
x = 1500
Therefore, the capacity of the tank is 1500 ml.
To find the capacity of the tank, we can use the given information about the initial amount and the increase in water level.
Let's assume the capacity of the tank is C ml.
According to the problem, initially, the tank was 1/5 full. Therefore, the amount of water in the tank was 1/5 of its capacity:
(1/5)C
When 700 ml of water was poured into the tank, it became 2/3 full. This means that the amount of water in the tank increased by 2/3 - 1/5 of its capacity, which is equal to 700 ml:
(2/3)C - (1/5)C = 700
To solve this equation for C, we need to find a common denominator. The least common multiple (LCM) of 3 and 5 is 15:
(10/15)C - (3/15)C = 700
(7/15)C = 700
Now, we can isolate C by multiplying both sides of the equation by 15/7:
C = (700 * 15) / 7
C = 3000
Therefore, the capacity of the tank is 3000 ml.