An elastic cord can be stretched to it's elastic limit by a load of 2n.if a 35cm length of the cord is extended 0.6cm by a force of 0.5n.what will be the length of the cord when the stretching force is2.5n
the ans is 352.8cm
It cannot be determined from the data given
K = 0.5N/0.0.6cm = 0.833 N/cm.
Length = 35 + 2N*1cm/0.833N = 37.40 cm.
Increasing the force above 2N do
not increase length further.