A solution of concentrated NaOH is 16.4 M. If the density of the solution is 1.43 g/mL what is the percent by mass NaOH?

% w/w = grams solute/100 g solution.

16.5M = 16.4 mols/L solution.
grams = mols x molar mass so 16.4 x 40 = ? grams NaOH/L solution and that divided by 10 = grams NaOH/100 mL of solution.
Then mass = volume x density. You know density and volume, that will give you the mass of 100 mL solution.
Then % w/w= (grams NaOH in that mass of solution)*100 = ?

Well, well, well! Looks like you have a "salty" problem on your hands. But don't fret, my friend, Clown Bot is here to help you solve it with a smile!

To find the percent by mass of NaOH, we need to determine the mass of NaOH present in the solution.

First, let's assume we have 100 mL of this concentrated NaOH solution. Since the density of the solution is 1.43 g/mL, the mass of the solution would be 100 mL * 1.43 g/mL = 143 g.

Now, let's calculate the amount of NaOH in this solution. The concentration of NaOH is given as 16.4 M, which means there are 16.4 moles of NaOH in 1 liter (or 1000 mL) of the solution.

To find the moles of NaOH in 100 mL, we use the formula: moles = concentration * volume.
So, moles = 16.4 M * (100 mL / 1000 mL) = 1.64 moles.

The molar mass of NaOH is calculated using the atomic mass of sodium (Na) + the atomic mass of oxygen (O) + the atomic mass of hydrogen (H). That's 22.99 g/mol + 16 g/mol + 1.01 g/mol, which gives us a total of approximately 40 g/mol.

Finally, we can calculate the mass of NaOH: mass = moles * molar mass = 1.64 moles * 40 g/mol = 65.6 g.

The percent by mass of NaOH is then calculated by dividing the mass of NaOH by the mass of the solution and multiplying by 100: percent by mass = (mass of NaOH / mass of solution) * 100 = (65.6 g / 143 g) * 100 = 45.8%.

So, the percent by mass of NaOH in the solution is approximately 45.8%. Ta-da! Problem solved, my friend!

To find the percent by mass of NaOH in the solution, we need to calculate the mass of NaOH in a given volume of the solution. Here's how you can do it step-by-step:

Step 1: Calculate the molar mass of NaOH.
The molar mass of NaOH = (1 atom of Na * atomic mass of Na) + (1 atom of O * atomic mass of O) + (1 atom of H * atomic mass of H)
= (1 * 22.99 g/mol) + (1 * 16.00 g/mol) + (1 * 1.01 g/mol)
= 22.99 g/mol + 16.00 g/mol + 1.01 g/mol
= 40.00 g/mol

Step 2: Convert the volume of the solution to grams.
Given that the density of the solution is 1.43 g/mL, we can convert the volume (in mL) of the solution to grams by multiplying with the density.
Volume of the solution = 1 mL

Mass of the solution = Volume of the solution * Density of the solution
= 1 mL * 1.43 g/mL
= 1.43 g

Step 3: Calculate the mass of NaOH in the solution.
Mass of NaOH = Volume of the solution * Molarity * Molar mass of NaOH
= 1.43 g * 16.4 M * 40.00 g/mol
= 23.55 g

Step 4: Calculate the percent by mass of NaOH.
Percent by mass = (Mass of NaOH / Mass of the solution) * 100
= (23.55 g / 1.43 g) * 100
= 1646.15%

Therefore, the percent by mass of NaOH in the solution is 1646.15%.

To find the percent by mass of NaOH in the solution, you need to calculate the mass of NaOH present in a given volume and then express it as a percentage in relation to the total mass of the solution.

First, we need to calculate the mass of NaOH in one liter of the solution. The molar mass of NaOH can be found by adding up the atomic masses of sodium (Na), oxygen (O), and hydrogen (H). The atomic masses are: Na = 22.99 g/mol, O = 16.00 g/mol, and H = 1.01 g/mol.

So, the molar mass of NaOH is:
(22.99 g/mol) + (16.00 g/mol) + (1.01 g/mol) = 40.00 g/mol

Now, we can calculate the mass of NaOH in one liter of the solution:
16.4 mole/L x 40.00 g/mol = 656 g/L

Since the density of the solution is given as 1.43 g/mL, we can convert the mass to grams per milliliter by dividing it by 1000:
656 g/L ÷ 1000 mL/L = 0.656 g/mL

Now, to find the percent by mass of NaOH, we need to compare the mass of NaOH to the total mass of the solution. The total mass of the solution can be found by multiplying the density by the volume.

Let's assume we have 100 mL of the solution:
Total mass of the solution = density x volume
Total mass of the solution = 1.43 g/mL x 100 mL = 143 g

Now, we can find the percent by mass of NaOH:
Percent by mass = (mass of NaOH / total mass of the solution) x 100
Percent by mass = (0.656 g / 143 g) x 100 ≈ 0.459 x 100 ≈ 45.9%

Therefore, the percent by mass of NaOH in the solution is approximately 45.9%.