Calculate the temperature in kelvin of a 2.5 mol sample at 8.3 atm in 45 L. Give your answer to 2 sig figs.
Which equation do I use to calculate temperature?
Is this a gas sample? Use PV = nRT
P = 8.3 atm
V = 45 L
n = 2.5 mols
R = 0.08206
T = ?
I tried to do (8.3atm)(45L)/(2.5)(.08206)=T
my final answer was 12K. Which was not correct. What step did I do wrong?
To calculate the temperature, we can use the Ideal Gas Law equation, which is:
PV = nRT
where P is the pressure in atmospheres (atm), V is the volume in liters (L), n is the number of moles, R is the gas constant, and T is the temperature in Kelvin (K).
Given the values:
- Pressure (P) = 8.3 atm
- Volume (V) = 45 L
- Number of moles (n) = 2.5 mol
To calculate the temperature (T), we need to rearrange the equation to solve for T:
T = PV / (nR)
Now we can substitute the values into the equation:
- P = 8.3 atm
- V = 45 L
- n = 2.5 mol
- R = 0.0821 L·atm/(mol·K) (universal gas constant)
T = (8.3 atm * 45 L) / (2.5 mol * 0.0821 L·atm/(mol·K))
Simplifying the expression:
T = (373.5 atm · L) / (0.20525 mol·L/atm·K)
T = 1816.6 K
Therefore, the temperature in Kelvin of a 2.5 mol sample at 8.3 atm in 45 L is approximately 1816.6 K, rounded to 2 significant figures.