A particle with a velocity of 2m / s at t = 0 moves along a straight line with a constant acceleration of 0.2m / s s.find the displacement of the particle in10 second
well, every second the velocity increases by 0.2 m/s. So how much is that after 10 seconds?
100.2
How did you get 100.2 ??
a = 2
v = at+c = 2t + c
when t = 0, v = 2
2 = 0 + c
v = 2t + 2
s = t^2 + 2t + k
when t=0 , s = 0 , thus k = 0
s = t^2 + 2t
when t = 10
s = 10^2 + 2(10) = 120
forget about my solution, I saw that as a = 2
instead of a = .2
so s = .1 t^2 + 2t
at t = 10
s = .1(100) + 2(10) = 30 m
To find the displacement of the particle after 10 seconds, we can use the equation of motion:
s = ut + (1/2)at^2
Where:
s = displacement
u = initial velocity
a = acceleration
t = time
Given:
u = 2 m/s
a = 0.2 m/s^2
t = 10 s
Let's substitute these values into the equation to find the displacement:
s = (2 * 10) + (1/2) * (0.2) * (10)^2
Simplifying this equation will give us the answer.