A mass of o.8 kg water at 25c is mixed with m kg of boiling water.The resultant temperature is 40c.Then find m is
To find the value of 'm', we can use the principle of conservation of energy.
The heat gained by the cooler water (0.8 kg) is equal to the heat lost by the hotter water (m kg).
The heat gained or lost by an object can be calculated using the formula:
Q = mcΔT
Where:
Q = Heat gained or lost
m = Mass of the substance
c = Specific heat capacity of the substance
ΔT = Change in temperature
For water, the specific heat capacity is approximately 4.18 J/g°C.
Here's how we can calculate the heat gained and lost:
Heat gained by cooler water:
Q1 = (0.8 kg) * (4.18 J/g°C) * (40°C - 25°C)
Heat lost by hotter water:
Q2 = (m kg) * (4.18 J/g°C) * (100°C - 40°C)
Since Q1 = Q2 (according to the principle of conservation of energy):
0.8 * 4.18 * (40 - 25) = m * 4.18 * (100 - 40)
Now, let's solve for 'm':
(0.8 * 4.18 * 15) / (60 * 4.18) = m
Simplifying further:
0.333 / 4.18 = m
m ≈ 0.08 kg
Therefore, the value of 'm' is approximately 0.08 kg.