The measured density oe He at NTP is 0.1784g/l.what is the weight of one mole?
To find the weight of one mole of helium (He), we need to determine its molar mass. In order to do that, we can use the ideal gas equation.
The ideal gas equation can be shown as:
PV = nRT
Where:
P = pressure (in atm)
V = volume (in liters)
n = number of moles
R = ideal gas constant (0.0821 L·atm/(mol·K))
T = temperature (in Kelvin)
Given that the density of helium at NTP (Normal Temperature and Pressure) is 0.1784 g/L, we can convert this value to a molar mass.
Density = mass (m) / volume (V)
Since the molar mass is typically expressed in grams per mole, we can rewrite the equation as:
Density = (molar mass) / (molar volume)
Molar volume is the volume occupied by one mole of gas at a given temperature and pressure. At NTP, one mole of any gas occupies 22.4 liters. So, we substitute the values into the equation and solve for the molar mass:
0.1784 g/L = (molar mass) / 22.4 L
Rearranging the equation, we get:
(molar mass) = 0.1784 g/L * 22.4 L
Now, we can calculate the molar mass:
(molar mass) = 3.987 g/mol
Therefore, the weight of one mole of helium is approximately 3.987 grams.
V=nRT/p
22.7ltr.
3.99
Huh ?
do you mean
The measured density of He at STP is 0.1784g/l.what is the weight of one mole?
If so
then
1 mole = 22.4 liters at STP
22.4 * .1784 = answer