The equation 1/14 (196x+17-10)=______ (20x+12x) has no solution. The equation (4x+24/122)=_____ (x+16/122)
Im sure the answer for the second one is 4, (4x+24/122) = 4 (x+6/122)
that is one of the scariest things I have seen in. my. LIFE.
AHHHHHHHHHHHHHHHHHHHHHHHHHHHHHH-
not sure what question is answered by the 4, but you are correct in assuming that the equation is an identity.
I am back.
HE. IS. BACK.
at first o.o now 0o0 what he!!---
To find the solution to the first equation, we can start by simplifying the equation.
1/14 (196x + 17 - 10) can be simplified as follows:
1/14 (196x + 7) = 1/14 * 7(28x + 1) = 1/14 * 7 * (28x + 1) = 1/2 * (28x + 1) = (28x + 1)/2
So the first equation becomes: (28x + 1)/2 = (20x + 12x)
Now, let's solve for x:
We can start by cross-multiplying to eliminate the denominators:
2 * (28x + 1) = (20x + 12x)
Distributing the 2 on the left side:
56x + 2 = 20x + 12x
Combining like terms:
56x + 2 = 32x
Subtracting 32x from both sides:
24x + 2 = 0
Subtracting 2 from both sides:
24x = -2
Dividing both sides by 24:
x = -2/24
Simplifying the fraction:
x = -1/12
Therefore, the solution to the first equation is x = -1/12.
Regarding the second equation, (4x + 24/122) = 4 (x + 6/122), you are correct. By distributing the 4 on the right side, the equation becomes:
4x + 24/122 = 4x + 24/122
Since the terms on both sides of the equation are the same, the equation holds true for all values of x. There are no restrictions or conditions on x in this equation, which means it is valid for any value of x. Therefore, any value of x will satisfy this equation, and it does not have a unique solution.