hello, write a quadratic equation in the form y=ax^2+bx+c, where a,b,c are all integers and the graph opens downward, whose roots are 3 and -6
steps in order to do this?
x = -6 and x = 3
so x+6 = 0 and x -3 =0
(x+6)(x-3) = 0
0 = x^2 +3x -18
This will open up.
0 = -x^2 - 3x +18 This will open down.
You can set this equal to y now.
If you work backwards.
Factor out the negative 1, factor the trinomial, you will can solve it and find the roots of 3 and -6. this is a good way to check your work.