1. A bag contains 9 green marbles and 11 white marbles. You select a marble at random. What are the odds in favor of you picking a green marble?
a. 9:20
b. 2:9
c. 11:9
d.9:11
my answer is d?
2. A bag contains 5 green marbles, 8 red marbles, 11 orange marbles, 7 brown marbles, and 12 blue marbles. you choose a marble, replace it, and chose again. what is P (red then blue?)
a. 20/43
b. 40/43
c. 20/ 1849
d. 96/1849
my answer is b?
3.(10) you have six $1 bills, eight $5 bills, two $10 bills, and four $20 bills in your wallet. You select a bill at random. without replacing the bill, you choose a second bill. what is P($!, then $10)?
a. 77/190
b.3/100
c.3/95
d.2/5
my answer is c?
4. A basket contains the following pieces of fruit: 3 apples, 2 oranges, 2 bananas, 2 pears, and 5 peaches. Jonas picks a fruit at random and does not replace it. Then beth picks a fruit at random. what is the probability that jonas gets a peach and beth gets an apple?
a. 15/182
b. 8/27
c. 4/91
d.15/196
my answer is b?
1. To find the odds in favor of picking a green marble, we need to compare the number of favorable outcomes (picking a green marble) to the number of possible outcomes.
The number of favorable outcomes is 9 (the number of green marbles).
The number of possible outcomes is 9 + 11 = 20 (the total number of marbles).
So the odds in favor of picking a green marble is 9:20.
The correct answer is option a. 9:20.
2. Since we are replacing the marble after each pick, the probability of picking a red marble and then a blue marble is the product of the individual probabilities.
The probability of picking a red marble is 8/43 (there are 8 red marbles out of a total of 43).
The probability of picking a blue marble is also 12/43.
So the probability of picking a red marble and then a blue marble is (8/43) * (12/43) = 96/1849.
The correct answer is option d. 96/1849.
3. Since we are not replacing the bill after the first pick, the probability of picking a $1 bill and then a $10 bill is the product of the individual probabilities.
The probability of picking a $1 bill is 6/20 (there are 6 $1 bills out of a total of 20 bills).
The probability of picking a $10 bill, given that a $1 bill has already been picked, is 2/19 (there are 2 $10 bills left out of a total of 19 bills after removing one $1 bill).
So the probability of picking a $1 bill and then a $10 bill is (6/20) * (2/19) = 3/95.
The correct answer is option c. 3/95.
4. Since Jonas does not replace the fruit after the first pick and Beth picks the fruit after Jonas, the probability of Jonas picking a peach and Beth picking an apple is the product of the individual probabilities.
The probability of Jonas picking a peach is 5/14 (there are 5 peaches out of a total of 14 fruits).
The probability of Beth picking an apple, given that a peach has already been picked, is 3/13 (there are 3 apples left out of a total of 13 fruits after removing one peach).
So the probability of Jonas picking a peach and Beth picking an apple is (5/14) * (3/13) = 15/182.
The correct answer is option a. 15/182.
1. To get the odds in favor of picking a green marble, we need to calculate the ratio of the number of favorable outcomes (green marbles) to the number of total outcomes (total number of marbles).
Number of green marbles = 9
Number of total marbles = 9 + 11 = 20
Odds in favor of picking a green marble = Number of green marbles : Number of total marbles
= 9 : 20
Therefore, the correct answer is a. 9:20.
2. To calculate the probability of picking a red marble first and then a blue marble with replacement, we need to multiply the probabilities of each event.
Probability of picking a red marble = Number of red marbles / Number of total marbles
= 8 / (5 + 8 + 11 + 7 + 12)
= 8 / 43
Probability of picking a blue marble = Number of blue marbles / Number of total marbles
= 12 / (5 + 8 + 11 + 7 + 12)
= 12 / 43
Probability of picking a red marble first and then a blue marble = Probability of picking red * Probability of picking blue
= (8/43) * (12/43)
Therefore, the correct answer is a. 20/43.
3. To find the probability of selecting a $1 bill followed by a $10 bill without replacement, we need to calculate the ratio of favorable outcomes to the total outcomes.
Number of $1 bills = 6
Number of $10 bills = 2
Total number of bills = 6 + 8 + 2 + 4 = 20
Probability of selecting a $1 bill first = Number of $1 bills / Total number of bills
= 6 / 20
= 3 / 10
Probability of selecting a $10 bill second (without replacing the first bill) = Number of $10 bills / Remaining bills after the first selection
= 2 / (20 - 1)
= 2 / 19
Probability of selecting a $1 bill first and then a $10 bill = Probability of selecting $1 * Probability of selecting $10
= (3/10) * (2/19)
Therefore, the correct answer is c. 3/95.
4. To calculate the probability of Jonas picking a peach and Beth picking an apple, we need to multiply the probabilities of each event.
Probability of Jonas picking a peach = Number of peaches / Number of total fruits
= 5 / (3 + 2 + 2 + 2 + 5)
= 5 / 14
Probability of Beth picking an apple (after Jonas has already picked a fruit) = Number of apples / Remaining fruits after Jonas' pick
= 3 / (14 - 1)
= 3 / 13
Probability of Jonas picking a peach and Beth picking an apple = Probability of Jonas picking peach * Probability of Beth picking apple
= (5/14) * (3/13)
Therefore, the correct answer is a. 15/182.
1.d
2.d
3.c
4.a
1) I agree
2) 8/43 times 12/43
3) I am not sure what the question is asking. There is a weird symbol.
4) no replacement
5/14 times 3/13