A pitcher throws a fast ball with a speed of 45m/s. The ball has a mass of 0.145kg. How much a) kinetic energy is given to the ball and b)What work was done in throwing the ball?

Vo=45 m/s
Mass= 0.145kg

A) KE?
KE= 1/2mV^2

A) 1.5x10^2 kg*m/s

B) WK=Change in KE
but I'm stuck not sure if these are the correct equations to use. Or if they are how to find work since I don't know the F or the D

well, I get 1.47*10^2 Joules

Yes, work done = change in kintic energy

thank you but looking at my notes it says work = Fcos thata d buthow do plot F and D that I do not have

work here is equal to the KE you calculated, you do not need force and distance the hand traveled.

so a and b are equal to the same Joules? Sorry I'm so confused

or do I need to use one of these equations

Fcos thata d= 1/2mVf^2-1/2mVo^2
or
F*D=1/2mVf^2-1/2mVo^2

got it thanks for your help

To calculate the kinetic energy (KE) of the ball, you can use the formula KE = 1/2mv^2, where m is the mass and v is the velocity.

a) Kinetic Energy (KE):
KE = 1/2 * 0.145 kg * (45 m/s)^2
KE = 1/2 * 0.145 kg * 2025 m^2/s^2
KE ≈ 14.64 joules

So, the kinetic energy given to the ball is approximately 14.64 joules.

b) To calculate the work done in throwing the ball, you need to know the force (F) and the distance (d). Since these values are not given, we can calculate the work done by using the change in kinetic energy.

Work (W) = ΔKE = KE_final - KE_initial

Since the ball starts from rest, the initial kinetic energy (KE_initial) is zero.

W = KE_final - KE_initial
W = KE_final - 0
W = KE_final

Therefore, the work done in throwing the ball is equal to the final kinetic energy.

Work (W) ≈ 14.64 joules.

So, the work done in throwing the ball is approximately 14.64 joules.