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Motion & Gravitation
A stone is dropped into a bore well 490m deep.after how time,the sound of splash of will be heard
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A stone is dropped into a bore well 490m deep.after how time,the sound of splash of will be heard
Top answer:
time=timetofall+timesoundup falling: 490=1/2 g t^2 or t=sqrt(2*490/g) soundup: 490=vsound*time
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A stone is dropped into a well of 80m deep. The sound of splash is heard 4.20 sec after the stone is dropped. Find the velocity
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The answer is not 500 it is 400
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A splash is heard 3.12s after a stone is dropped into a well 45m deep.the speed of sound in air is(g=10m/s2)
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The time when the stone reaches the ground =(45*2)/10=3 sec.so,time taken by sound = 3.12-3= 0.12
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1. A stone is dropped from rest into a well. The sound of the splash is heard exactly 1.50 s later. Find the depth of the well
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I will be happy to critique your thinking or work.
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1. A stone is dropped from rest into a well. The sound of the splash is heard exactly 1.50 s later. Find the depth of the well
Top answer:
To solve these problems, we will need to use some equations and concepts related to the speed of
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1. A stone is dropped from rest into a well. The sound of the splash is heard exactly 1.50 s later. Find the depth of the well
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10
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A spelunker drops a stone from rest into a hole. The speed of sound is 343 m/s in air, and the sound of the stone striking the
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The time required to hear the impact is the sum of the time for the stone to fall and the time for
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A stone is dropped into a well of depth 11 m. How long after that, the sound of the splash can be heard? Given speed of sound
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To find out how long it takes for the sound of the splash to be heard after the stone is dropped
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A spelunker (cave explorer) drops a stone from rest into a hole. The speed of sound is 343 m/s in air, and the sound of the
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Well, let's calculate that, shall we? Since the speed of sound is 343 m/s and it takes 3.24 seconds
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A spelunker drops a stone from rest into a hole. The speed of sound is 343m/s in air, and the sound of the stone striking the
Top answer:
time=time down + time up time=sqrt(2h/g)+ h/vsound solve for time Use the quadratic equation.
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