Find three consecutive no.whose product is 10626
The three numbers will therefore be close to 21.98. So, I'd say they'd be
21,22,23 whose product is 10626
The cube root of 10,626 = 21.98
Take it from there.
To find three consecutive numbers whose product is 10,626, we can solve it mathematically:
Let the first number be x.
The second number will be x + 1 (as it is the consecutive number after x).
The third number will be x + 2 (as it is the consecutive number after x + 1).
So, the equation becomes:
x * (x + 1) * (x + 2) = 10,626
Expanding and simplifying:
x^3 + 3x^2 + 2x - 10,626 = 0
Solving this equation requires either solving it using numerical methods or using a graphing calculator. After solving it, we find that the first number is x = 21. Therefore, the three consecutive numbers whose product is 10,626 are 21, 22, and 23.
To find three consecutive numbers whose product is 10626, you can use algebraic equations:
Let's assume the three consecutive numbers as n, n+1, and n+2. Then the product of these three numbers is:
n * (n + 1) * (n + 2) = 10626
Now, we can simplify this equation and solve for n:
n^3 + 3n^2 + 2n - 10626 = 0
To find the values of n, we can use trial and error or employ a numerical method like the Newton-Raphson method or the bisection method. However, in this case, trial and error will be more straightforward because the number 10626 is not very large.
By checking different values of n, we can find that n = 22 satisfies the equation:
22 * (22 + 1) * (22 + 2) = 10626
Therefore, the three consecutive numbers are 22, 23, and 24.