How many grams of ethanol are formed from the complete conversion of37.5g of sucrose
To determine the number of grams of ethanol formed from the complete conversion of sucrose, we need to know the balanced chemical equation for the reaction between sucrose and ethanol. The balanced chemical equation for the fermentation of sucrose into ethanol is:
C12H22O11 + H2O → 4C2H5OH + 4CO2
From the balanced equation, we can determine the stoichiometric ratio of sucrose to ethanol. According to the equation, one mole of sucrose (C12H22O11) reacts to form four moles of ethanol (C2H5OH).
First, we need to convert the given mass of sucrose (37.5g) to moles. The molar mass of sucrose is 342.3 g/mol.
Moles of sucrose = mass of sucrose / molar mass of sucrose
Moles of sucrose = 37.5g / 342.3 g/mol
Next, we use the stoichiometry from the balanced chemical equation to determine the moles of ethanol produced.
Moles of ethanol = Moles of sucrose × (4 moles of ethanol / 1 mole of sucrose)
Finally, we convert the moles of ethanol back to grams using the molar mass of ethanol, which is approximately 46.07 g/mol.
Grams of ethanol = Moles of ethanol × molar mass of ethanol
Grams of ethanol = Moles of ethanol × 46.07 g/mol
By following these steps, you can calculate the exact number of grams of ethanol formed from the complete conversion of 37.5g of sucrose.