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Mathematics
For each sequence, find the next four terms 2,4,6,8...
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you kidding me?
You can't count by twos?
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The fifth ninth and sixteenth terms of a linear sequence ( ap) are consecutive terms of an exponential sequence
1 find the common
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(a+8d)/(a+4d) = (a+15d)/(a+8d) so, 3a=4d #1. a = 4/3 d #2. You can pick your values for a and d,
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DOING A 20 QUESTION MATH TEST AND GOT STUCK ON THESE PROBLEMS!!:(
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in an arithmetic sequence whose first term is 4, the 1st, 3rd and 7th terms form consecutive terms of geometric sequence, find
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a + a+d + a+2d = 3 a + 3 d = 3(a+d)=12+3d firat = 4 third = 4+2d 7th = 4+6d r and the geometric is
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The 5th,9th and 16th terms of a linear sequence A.P are consecutive terms of an exponential sequence.Find the common difference
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since the GP has a common ratio, (a+8d)/(a+4d) = (a+15d)/(a+8d) (a+8d)^2 = (a+15d)(a+4d)
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Hello!! Can anyone help me with this practice?
1)Find the next two terms of the sequence. 2,6,10,14 2)Find the next two terms of
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Hello Sorry!! Haha, beat you, Romantic killer! Tips:☺ Answers:☻ Anyways here ya go! ☻1)18,22
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The 5th,9th and 16th terms of a linear sequence are consecutive terms of an exponential sequence G.P. find the common difference
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since AP has a constant difference, and GP has a constant ratio, A9/a5 = a16/a9 (a+8d)^2 =
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the sum of the first nine terms of an arithmetic sequence 216. The 1st, 3rd and 7th terms form the first three terms of a
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9/2 (2a+8d) = 216 (a+2d)/a = (1+6d)/(a+2d) One choice is 24, 24, 24, ... Probably not what you want.
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The first and second terms of an exponential sequence (GP) are respectively the first and third terms of a linear sequence (AP)
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I don't understand this question Can you show the full wokings
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The first and second terms of an exponential sequence (G.P) are respectively the first and third terms of a linear sequence
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let the GP be a , ar, ar^2 , ar^3, ... the arithmetic (linear) sequence is a , a+d , a+2d , a + 3d ,
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