Could you please help me with this question? Simplify 6/Square root of 3-2.

Also, could you help me with the steps on how to figure it? Thank you.
a.4/square root of 3
b. 12-6 to the square root of 3
c. Square root of 3-2
d. 3

6/(√3-2)

recall that (a-b)(a+b) = a^2-b^2

multiply top and bottom by (√3+2) and you have

6(√3+2)
----------------
(√3-2)(√3+2)

= (6√3+12/(3-4)
= -6√3-12

check your text for typos. It looks like B except for the extra minus sign.