The distance between town A and town B was 210 km. At 9:20 pm, a bus set off from town A to town B and a car from town B to town A. The average speed of the bus was 60 km/h, and the average speed of the car was 80 km/h. a) Calculate the time at which the car passed the bus.
b) How far had the car traveled when it passed the bus?
a. Vb*t + Vc*t = 210.
60t + 80t = 210, t = ?.
b. d = Vc*t.
To calculate the time at which the car passed the bus and how far the car had traveled at that point, we need to determine the time it takes for both vehicles to meet.
a) To calculate the time at which the car passed the bus, we can use the concept of relative speed. The relative speed is the difference in the speeds of the two vehicles traveling in opposite directions.
The relative speed of the car with respect to the bus is the sum of their individual speeds: 80 km/h + 60 km/h = 140 km/h.
Since the distance between the two towns is 210 km, the time it takes for both vehicles to meet can be calculated using the formula:
Time = Distance / Speed
Time = 210 km / 140 km/h = 1.5 hours
Therefore, the car and the bus will meet 1.5 hours after they started.
To find the time at which the car passed the bus, we can add 1.5 hours to the departure time of the bus, which is 9:20 pm.
9:20 pm + 1.5 hours = 10:50 pm
Therefore, the car passed the bus at 10:50 pm.
b) To find how far the car had traveled when it passed the bus, we can calculate the distance covered by the car during 1.5 hours.
Distance = Speed x Time
Distance = 80 km/h x 1.5 hours = 120 km
Therefore, when the car passed the bus, it had traveled 120 km.