Two charges +1C and -1C are placed at distance 1m apart ,each having masses 2kg respectively are released.what is the type of collision they experience?
To determine the type of collision experienced by the two charges, we need to consider the forces acting on them and their initial velocities.
Given:
Charge 1: q1 = +1C
Charge 2: q2 = -1C
Distance between charges: d = 1m
Mass of each charge: m1 = m2 = 2kg
Since the charges have opposite charges, they will exert an electrostatic force on each other given by Coulomb's law:
F = k * |q1 * q2| / r^2,
where F is the magnitude of the electrostatic force, k is Coulomb's constant, q1 and q2 are the charges, and r is the distance between the charges.
In this case, since the distance is 1m and the charges are equal in magnitude, the electrostatic force will be:
F = k * |1 * 1| / 1^2
F = k
Since the magnitudes of the charges are the same, the electrostatic force will be attractive. The charges will accelerate towards each other due to this force.
Now, let's consider their initial velocities. The problem states that they are released, which imples that they were initially at rest.
In a collision, the type of collision is determined by the initial and final velocities of the objects involved.
In this case, since the charges were initially at rest, their initial velocities are zero. After the collision, they will experience an attractive electrostatic force and therefore accelerate towards each other. The final velocities will depend on the specific situation and cannot be determined with the information given.
Based on this information, we can conclude that the collision between the charges is an inelastic collision.
To determine the type of collision that the charges experience, we need to consider the conservation of momentum and the conservation of kinetic energy.
In this scenario, the charges are released from rest, meaning they have an initial velocity of zero. After release, they will accelerate towards each other due to the electric force between them.
Since the charges have equal magnitudes but opposite signs, the electric force between them is attractive. So, both charges will accelerate towards each other.
Now, let's consider the possible outcomes:
1. Elastic collision: In an elastic collision, both momentum and kinetic energy are conserved. If the charges were to collide elastically, they would repel each other after collision with the same speeds they had before the collision. However, since the charges have the same mass and opposite charge, they would continue accelerating together indefinitely, violating the conservation of energy. Therefore, this collision cannot be elastic.
2. Inelastic collision: In an inelastic collision, momentum is conserved, but kinetic energy is not. If the charges were to collide inelastically, they would stick together after the collision. However, as mentioned earlier, due to the attractive force between them, they will continue to accelerate towards each other indefinitely. Therefore, this collision cannot be inelastic either.
Based on the above analysis, we can conclude that the charges do not experience a collision in the traditional sense. Instead, they will continue to accelerate towards each other indefinitely due to the attractive electric force.