Lieutenant Wharf, of mass 98.3 kg, is outside the space shuttlecraft Enigma trying to repair a broken warp engine nacelle. He finds he has drifted away from the shuttle while carelessly daydreaming. Miraculously, a stray photon torpedo casing (mass 2,020 kg) appears. Wharf uses this casing to get back to the shuttle by pushing against the casing. If the casing moves directly away from the shuttle after this push with a speed 0.2 m/s, and it then takes him 5.5 seconds to reach the shuttle again, how far away was he from the shuttle, in m?

Well, it seems like Lieutenant Wharf had quite the situation on his hands! Now, let's use our clown physics to solve this problem in a hilarious way.

Since Lieutenant Wharf is a brave and resourceful guy, let's imagine that he decides to ride the stray photon torpedo casing like a cowboy on a bucking bronco. Yeehaw!

Now, let's gather our funny physics arsenal. We know the mass of Lieutenant Wharf, which is 98.3 kg, and the recoil speed of the casing, which is 0.2 m/s. Additionally, we have the time it takes for him to reach the shuttle again, which is 5.5 seconds.

To calculate the distance, we can use the equation:

(distance) = (recoil speed) * (time)

Plugging in the values we have:

(distance) = 0.2 m/s * 5.5 s

And voila! We get:

(distance) = 1.1 meters

Therefore, Lieutenant Wharf found himself 1.1 meters away from the shuttlecraft Enigma while drifting in space. I guess you could say he took a small detour on his way back.

To solve this problem, we can use the principle of conservation of momentum. The total momentum before the push is equal to the total momentum after the push.

The momentum before the push is given by the product of the mass of Lieutenant Wharf (m1) and his initial velocity (v1). The momentum after the push is given by the product of the mass of the photon torpedo casing (m2) and its final velocity (v2).

The equation for conservation of momentum can be written as:

(m1 * v1) + (m2 * v2) = 0

Let's substitute the given values into the equation:

(98.3 kg * 0 m/s) + (2020 kg * -0.2 m/s) = 0

Simplifying the equation:

-404 kg * m/s = 0

Since the equation equals zero, it means the total momentum before and after the push is zero. This indicates that the mass of Lieutenant Wharf multiplied by his initial velocity must be equal to the mass of the photon torpedo casing multiplied by its final velocity.

Now, we can solve for the initial velocity (v1) of Lieutenant Wharf using the equation:

m1 * v1 = m2 * v2

v1 = (m2 * v2) / m1

Substituting the given values:

v1 = (2020 kg * 0.2 m/s) / 98.3 kg

v1 = 4.108 m/s

Now, let's calculate the distance Lieutenant Wharf was from the shuttle using the formula:

distance = v * t

Where v is the initial velocity and t is the time taken to reach the shuttle again.

distance = 4.108 m/s * 5.5 s

distance = 22.594 m

Therefore, Lieutenant Wharf was 22.594 meters away from the shuttle.

To solve this problem, we can use the principle of conservation of momentum. The total momentum before Wharf pushes the photon torpedo casing is zero since he and the casing are initially at rest.

Momentum is defined as the product of mass and velocity. The momentum of the casing after Wharf pushes it is given by the formula:

Momentum = mass * velocity

The momentum of the casing is equal in magnitude and opposite in direction to Wharf's momentum. We can set up an equation using the principle of conservation of momentum as follows:

Wharf's momentum = Casing's momentum

(mass of Wharf * velocity of Wharf) = (mass of casing * velocity of casing)

(98.3 kg * 0 m/s) = (2020 kg * 0.2 m/s)

Rearranging the equation to solve for the mass of Wharf:

mass of Wharf = (mass of casing * velocity of casing) / velocity of Wharf

mass of Wharf = (2020 kg * 0.2 m/s) / 0.2 m/s

mass of Wharf = 2020 kg

The mass of Wharf is found to be 2020 kg.

Now, to calculate the distance Wharf drifted away from the shuttle, we can use the formula:

Distance = velocity * time

Distance = 0.2 m/s * 5.5 s

Distance = 1.1 m

Therefore, Wharf was 1.1 meters away from the shuttle when he drifted.

Use the impulse formula to solve for acceleration, solve for d using kinematics.