Combustion of hydrogen sulphide with oxygen

in kmol H2S +O2 = H2O + SO2 can somebody balance this for me and break it down to the atomic mass.

2H2S +3O2 = 2H2O + 2SO2

That's balanced. I don't know you mean by "breaking it down".

To balance the chemical equation for the combustion of hydrogen sulfide (H2S) with oxygen (O2) to form water (H2O) and sulfur dioxide (SO2), you need to ensure that there is the same number of each type of atom on both sides of the equation. Here's how to balance it:

1. Start by counting the number of each type of atom on each side of the equation:
Hydrogen (H): 2 on the left, 2 on the right
Sulfur (S): 1 on the left, 1 on the right
Oxygen (O): 2 on the left, 2 on the right

2. Begin with the elements that appear in only one compound on each side. In this case, sulfur is a good choice.

Place a coefficient in front of SO2 to balance the sulfur atoms:
H2S + O2 → H2O + 2SO2

3. Now, look at the oxygen atoms. In this case, we have 2 oxygen atoms on the left side and 4 oxygen atoms on the right side.

To balance the oxygen atoms, place a coefficient in front of O2 on the left side:
H2S + 2O2 → H2O + 2SO2

4. Finally, verify that all the atoms are balanced:
Hydrogen: 2 on the left, 2 on the right
Sulfur: 1 on the left, 1 on the right
Oxygen: 4 on the left, 4 on the right

The balanced equation is:
H2S + 2O2 → H2O + 2SO2

Now, let's break it down to atomic mass using the molar masses of the elements involved:

- Atomic mass of hydrogen (H): 1 g/mol
- Atomic mass of sulfur (S): 32.07 g/mol
- Atomic mass of oxygen (O): 16 g/mol

Using these values, we can calculate the molar masses of the compounds involved:

- Molar mass of H2S: (2 × 1 g/mol) + 32.07 g/mol = 34.07 g/mol
- Molar mass of O2: 2 × 16 g/mol = 32 g/mol
- Molar mass of H2O: (2 × 1 g/mol) + 16 g/mol = 18 g/mol
- Molar mass of SO2: 32.07 g/mol + (2 × 16 g/mol) = 64.07 g/mol

The balanced equation, H2S + 2O2 → H2O + 2SO2, tells us that for every 34.07 grams of hydrogen sulfide, we need 64.07 grams of sulfur dioxide, produce 18 grams of water, and require 32 grams of oxygen gas.