Question

A drop of liquid is about 0.05 mL. When doing a titration lab, 73 drops of base were used to reach end point; how many liters of base were required to neutralize the acid?

Answer 1

73 drops x (0.05 mL/drop) x 73 = approx 3.5 mL but that's only an estimate. Recalculate more exactly, then convert to L.