What is the volume of stone in an Egyptian with a square base of side 100m and a slant height of 50m for each of the triangular face.
that's a strange shaped Egyptian, but assuming he is pyramidal in shape, the height h is found using
h^2 = (100/2)^2-50^2
huh?
If the sides have a slant height of half the base width, the pyramid is totally flat!
What is the volume of stone in an Egyptian with a square base of side 100m and a slant height of 50m for each of the triangular face
To find the volume of the Egyptian pyramid, we need to find the volume of the stone.
The pyramid has a square base with a side length of 100m. This means the area of the base is 100m x 100m = 10,000m².
The height of the pyramid can be found using the Pythagorean theorem. Since we know the slant height and the base side length, we can find the height using the formula:
height = √(slant height^2 - base side length/2^2)
In this case, the slant height is 50m and the base side length is 100m. Plugging these values into the formula:
height = √(50m^2 - 100m/2^2)
= √(2500m^2 - 2500m^2)
= √(0m^2)
= 0m
This means the height of the pyramid is 0m, which is not possible. It seems there might be an error in the provided slant height or base side length values. Please double-check the measurements or provide more information for an accurate calculation.