How does changing the volume of strontium nitrate solution, added to 8 cm3 of sodium carbonate solution, affect the amount of precipitate formed?
Is it the more the strontium nitrate solution is increased, the more precipate formed?
Sr(NO3)2 + Na2CO3 ==> SrCO3(s) + 2NaNO3
As long as Na2CO3 is available (not all of it has reacted) adding Sr(NO3)2 forms more and more of the ppt of SrCO3. But even after all of the Na2CO3 is used, then increasing Sr(NO3)2 becomes a common ion and the Ksp dictates that the solubility of the ppt decrease.
To understand how changing the volume of strontium nitrate solution affects the amount of precipitate formed, we first need to consider the chemical reaction that takes place between strontium nitrate (Sr(NO3)2) and sodium carbonate (Na2CO3). The reaction is as follows:
Sr(NO3)2 + Na2CO3 → SrCO3 + 2NaNO3
In this reaction, strontium nitrate reacts with sodium carbonate to produce strontium carbonate and sodium nitrate.
Now, let's consider the given scenario: 8 cm3 of sodium carbonate solution is mixed with an unknown volume of strontium nitrate solution.
When strontium nitrate is added to the sodium carbonate solution, the reaction occurs and produces strontium carbonate (SrCO3) as a precipitate. The amount of precipitate formed depends on the limiting reactant of the reaction. The limiting reactant is the one that is completely consumed first and determines the maximum amount of product formed.
In this case, the balanced equation shows that 1 mole of strontium nitrate reacts with 1 mole of sodium carbonate to produce 1 mole of strontium carbonate. Therefore, the molar ratio between strontium nitrate and strontium carbonate is 1:1.
So, the amount of strontium carbonate formed will depend on the amount of strontium nitrate available in comparison to sodium carbonate. If the volume of the strontium nitrate solution is increased, more strontium nitrate is available for the reaction. As a result, more strontium carbonate will be formed.
Therefore, to answer your question, yes, increasing the volume of the strontium nitrate solution will indeed lead to the formation of more precipitate (strontium carbonate).