calculation of prepaired tris buffer 0.02mol/lit , ph 9.0

To calculate the preparation of a Tris buffer solution with a desired concentration and pH, you need to know the molecular weight of Tris base (Tris(hydroxymethyl)aminomethane) and the pKa value of the acid-base equilibrium of Tris.

Here are the steps to calculate the preparation of a Tris buffer solution with a concentration of 0.02 mol/l and a pH of 9.0:

1. Calculate the volume of the buffer solution you want to prepare. This depends on how much final volume you need. Let's assume you want to prepare 1 liter of buffer solution.

2. Determine the molar mass of Tris base. The molar mass of Tris base is 121.14 g/mol.

3. Calculate the number of moles of Tris base needed using the desired concentration. The concentration is given as 0.02 mol/liter. Therefore, you will need 0.02 mol of Tris base for 1 liter of buffer solution.

4. Prepare a Tris solution containing the calculated number of moles of Tris base. Dissolve the calculated mass of Tris base in a smaller volume of distilled water. Calculate the mass of Tris base using the formula:
Mass (g) = Moles × Molar mass
Mass (g) = 0.02 mol × 121.14 g/mol = 2.42 g

5. Once the calculated mass of Tris base is dissolved in a smaller volume (e.g., 500 ml) of distilled water, transfer the solution to a measuring cylinder or volumetric flask.

6. Adjust the pH of the solution to 9.0 using a pH meter or pH indicator and either hydrochloric acid (HCl) or sodium hydroxide (NaOH) solutions. To increase the pH from neutral to 9.0, you will need to add a base like NaOH. Please note that you need to be cautious while adjusting the pH, as sudden changes in pH can affect the accuracy of your measurements.

7. Finally, once the pH reaches 9.0, add distilled water to make up the final volume to 1 liter. This will ensure that the desired concentration and pH are obtained for your Tris buffer solution.

Remember to always double-check your calculations and measurements to ensure accuracy in the preparation of any buffer solution.