The perimeter of the rectangle is 120 units what is its area in square units
L=3n
W= n
What formula do I use?
A) 675
B) 900
C) 1225
D) 2700
Perimeter is the sum of all sides. For a rectangle, P = 120 = 2L + 2W.
You are given that
L = 3n
W = n,
so you can now do a substitution into the perimeter equation:
120 = 2(3n) + 2(n).
Simplifying this, we get 120 = 8n, so n = 15.
Revisiting our length and width equations,
L = 3(15) = 45
W = 15
Area is length * width, which is A) 675 units.
(BTW, love the username.)
To find the area of a rectangle, you need to multiply its length by its width. In this case, the length (L) is given by 3n, and the width (W) is given by n.
So, the formula to find the area (A) of the rectangle is: A = L × W
Substituting the given values, we have: A = (3n) × n = 3n^2
Now, we are given that the perimeter of the rectangle is 120 units. The perimeter of a rectangle is calculated by adding all four sides, which in this case would be: P = 2L + 2W
Plugging in the given values, we have: 120 = 2(3n) + 2n
Simplifying, we get: 120 = 6n + 2n
Combining like terms, we have: 120 = 8n
To solve for n, divide both sides of the equation by 8: n = 120/8 = 15
Now that we have the value of n, we can substitute it back into the formula for area: A = 3n^2 = 3(15)^2 = 675
Therefore, the area of the rectangle is 675 square units.
So, the correct answer is A) 675.