Find the area of the region enclosed by the intersection of the circle x^2+y^2=4 and the parabola y=x^2. Show work
The curves intersect at (±1.25,1.56)
using symmetry, the area is
a = 2∫[0,1.25] √(4-x^2) - x^2 dx = 3.35
using symmetry, the area is
a = 2∫[0,1.25] √(4-x^2) - x^2 dx = 3.35