Calculate the heat necessary to raise the temperature of 500kg of water in the generator of the refrigerator from 10degree Celsius to 40degree Celsius. The specific heat capacity of water equal to 4.2kj/kgk
heat=mass*specificheat*changetemp
=500kg*4.2kJ/kg-K*(40-10)C
now note on units, a Celcius degree change is the same as kelvins degree change, so your units will end up dividing, and leaving kJ
To calculate the heat necessary to raise the temperature of an object, you can use the formula:
Q = m * c * ΔT
Where:
Q is the heat transferred in joules (J)
m is the mass of the object in kilograms (kg)
c is the specific heat capacity of the substance in joules per kilogram per degree Celsius (J/kg°C)
ΔT is the change in temperature in degrees Celsius (°C)
In this case, we have:
m = 500 kg (mass of water)
c = 4.2 kJ/kg°C (specific heat capacity of water)
ΔT = 40°C - 10°C = 30°C (change in temperature)
First, let's convert the specific heat capacity from kJ/kg°C to J/kg°C:
c = 4.2 kJ/kg°C * 1000 J/1 kJ = 4200 J/kg°C
Now we can plug the given values into the formula and solve for Q:
Q = 500 kg * 4200 J/kg°C * 30°C
Q = 6,300,000 J
Therefore, the heat necessary to raise the temperature of 500 kg of water from 10°C to 40°C is 6,300,000 joules (J).