Write the molecular, total ionic, and net ionic, for the reaction.

1). Aqueous sodium carbonate is reacted with aqueous nickle (11) chloride.

2). Aqueous potassium hydroxide is mixed with aqueous hydrochloric acid.

You add the aq and l and s.

Molecular equation:
Na2CO3 + NiCl2 ==> 2NaCl + NiCO3(s)

Total ionic equation:
2Na^+ + CO3^2- + Ni^2+ + 2Cl^- ==> 2Na^+ + 2Cl^- + NiCO3(s)

Net ionic equation: Just cancel the ions that are common to both sides. What left is the net ionic equation.
CP3^2-(aq) + Ni^2+(aq) ==> NiCO3(s)

Do the same for the other one.

1) Aqueous sodium carbonate is reacted with aqueous nickel (II) chloride.

Molecular Equation:
Na2CO3(aq) + NiCl2(aq) → 2NaCl(aq) + NiCO3(s)

Total Ionic Equation:
2Na+(aq) + CO3^2-(aq) + Ni^2+(aq) + 2Cl^-(aq) → 2Na+(aq) + 2Cl^-(aq) + NiCO3(s)

Net Ionic Equation:
CO3^2-(aq) + Ni^2+(aq) → NiCO3(s)

2) Aqueous potassium hydroxide is mixed with aqueous hydrochloric acid.

Molecular Equation:
KOH(aq) + HCl(aq) → KCl(aq) + H2O(l)

Total Ionic Equation:
K+(aq) + OH^-(aq) + H+(aq) + Cl^-(aq) → K+(aq) + Cl^-(aq) + H2O(l)

Net Ionic Equation:
OH^-(aq) + H+(aq) → H2O(l)

To determine the molecular, total ionic, and net ionic equations for each reaction, we need to write out the reactants and products and then identify the spectator ions (ions that are present on both sides of the equation and do not participate in the reaction).

1) Aqueous sodium carbonate reacts with aqueous nickel (II) chloride.

First, let's write out the balanced molecular equation:

Na2CO3(aq) + NiCl2(aq) → 2NaCl(aq) + NiCO3(s)

The reactants are aqueous sodium carbonate (Na2CO3) and aqueous nickel (II) chloride (NiCl2), while the products are sodium chloride (NaCl) and nickel carbonate (NiCO3).

Next, let's write out the total ionic equation by separating all the ionic compounds into their individual ions:

2Na+(aq) + CO3^2-(aq) + Ni^2+(aq) + 2Cl-(aq) → 2Na+(aq) + 2Cl-(aq) + NiCO3(s)

In the total ionic equation, the aqueous compounds are written as their dissociated ions, while the solid compound (nickel carbonate) remains unchanged.

Now, let's identify the spectator ions (ions present on both sides of the equation):

Na+ and Cl-

Finally, let's write the net ionic equation, which removes the spectator ions from the total ionic equation:

CO3^2-(aq) + Ni^2+(aq) → NiCO3(s)

So, the net ionic equation for this reaction is CO3^2-(aq) + Ni^2+(aq) → NiCO3(s).

2) Aqueous potassium hydroxide is mixed with aqueous hydrochloric acid.

First, let's write out the balanced molecular equation:

KOH(aq) + HCl(aq) → KCl(aq) + H2O(l)

The reactants are aqueous potassium hydroxide (KOH) and aqueous hydrochloric acid (HCl), while the products are potassium chloride (KCl) and water (H2O).

Next, let's write out the total ionic equation by separating all the ionic compounds into their individual ions:

K+(aq) + OH-(aq) + H+(aq) + Cl-(aq) → K+(aq) + Cl-(aq) + H2O(l)

In the total ionic equation, the aqueous compounds are written as their dissociated ions, while the liquid compound (water) remains unchanged.

Now, let's identify the spectator ions (ions present on both sides of the equation):

K+ and Cl-

Finally, let's write the net ionic equation, which removes the spectator ions from the total ionic equation:

OH-(aq) + H+(aq) → H2O(l)

So, the net ionic equation for this reaction is OH-(aq) + H+(aq) → H2O(l).